The far point of a myopic person is 80 cm in front of the eye.

Question.
The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem ?

solution:
For myopia, focal length is given by,

$\mathrm{f}=-\mathrm{x}=-80 \mathrm{~cm}=-\mathbf{0 . 8} \mathrm{m}$

Power, $\mathrm{P}=\frac{1}{\mathrm{f}}=\frac{1}{-0.8}$

$=-1.25$ dioptres.

The lens is a concave lens.

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now