The first term of an A.P. is p and its common difference is q. Find its 10th term.

Here, we are given,

First term (a) = p

Common difference (d) = q

We need to find the 10th term (an).

As we know,

$a_{n}=a+(n-1) d$

So, for 10th term (n = 10), we get,

$a_{10}=p+(10-1) q$

$=p+9 q$

Therefore, $a_{10}=p+9 q$