The four arms of a Wheatstone


The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of $15 \Omega$ resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of $10 \mathrm{~V}$ is maintained across AC.

  1. $2.44 \mu \mathrm{A}$

  2. $2.44 \mathrm{~mA}$

  3. $4.87 \mathrm{~mA}$

  4. $4.87 \mu \mathrm{A}$

Correct Option: , 3



$53 x-20 y=30$..(1)


$17 y-4 x=10$..(2)

on solving (1) \& (2)



$\Delta \mathrm{V}=0.073 \mathrm{R}=15 \Omega$

$\mathrm{i}=4.87 \mathrm{~mA}$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now