Question:
The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.
Solution:
Let the two numbers be a and b.
Let the value of a be 161.
Given: HCF = 23 and LCM = 1449
we know, a × b = HCF × LCM
⇒ 161 × b = 23 × 1449
$\Rightarrow \quad \therefore b=\frac{23 \times 1449}{161}=\frac{33327}{161}=207$
Hence, the other number b is 207.
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