# The HCF of two numbers is 23 and their LCM is 1449.

Question:

The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.

Solution:

Let the two numbers be and b.
​Let the value of be 161.
Given: HCF = 23 and LCM = 1449
we know,        × b = HCF ​× LCM
⇒     161 × b = 23 × 1449

$\Rightarrow \quad \therefore b=\frac{23 \times 1449}{161}=\frac{33327}{161}=207$

Hence, the other number b is 207.