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The image of the line

Question:

The image of the line $\frac{x-1}{3}=\frac{y-3}{1}=\frac{z-4}{-5}$ in the plane $2 x-y+z+3=0$ is the line:

  1. $\frac{\mathrm{x}+3}{3}=\frac{\mathrm{y}-5}{1}=\frac{\mathrm{z}-2}{-5}$

  2. $\frac{x+3}{-3}=\frac{y-5}{-1}=\frac{z+2}{5}$

  3. $\frac{x-3}{3}=\frac{y+5}{1}=\frac{z-2}{-5}$

  4. $\frac{x-3}{-3}=\frac{y+5}{-1}=\frac{z-2}{5}$


Correct Option: 1

Solution:

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