The income of a person is Rs 300,000 in the first year and he receives an increase of Rs 10000

Let $S_{n}$ denote the total amount the person receives in $n$ years.

Let d be the common increment in his income every year.

Let a denote the initial income of the person.

$S_{20}=\frac{20}{2}\{2 \times 300,000+(20-1) 10,000\}$

$=79,00,000$

Therefore, the total amount the person receives in 20 years is Rs 79,00,000.

Here, a = 300,000, d = 10000, n = 20

Total amount at the end of 20 years: