Question:
The length of a second’s pendulum on the surface of the earth is 1 m. What will be the length of a second’s pendulum on the moon?
Solution:
The time period of a simple pendulum, T = 2π√l/g
Where l is the length of the pendulum and g is the acceleration due to gravity
Therefore, lmoon/gmoon = learth/gearth = 1/6 m
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