Question:
The lengths of the diagonals of a rhombus are 12 cm and 16 cm. The area of the rhombus is
(a) $192 \mathrm{~cm}^{2}$
(b) $96 \mathrm{~cm}^{2}$
(c) $64 \mathrm{~cm}^{2}$
(d) $80 \mathrm{~cm}^{2}$
Solution:
(b) $96 \mathrm{~cm}^{2}$
Area of the rhombus $=\frac{1}{2} \times$ product of diagonals $=\frac{1}{2} \times 12 \times 16=96 \mathrm{~cm}^{2}$
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