Question:
The maximum and minimum amplitude of an amplitude modulated wave is $16 \mathrm{~V}$ and $8 \mathrm{~V}$ respectively. The modulation index for this amplitude modulated wave is $x \times 10^{-2}$. The value of $x$ is
Solution:
Modulation index $=\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }}$
$=\frac{16-8}{16+8}=\frac{8}{24}=\frac{1}{3}=0.33$
$x \times 10^{-2}=0.33$
$x=33$
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