The normal reaction 'N' for a vehicle of

Question:

The normal reaction ' $\mathrm{N}$ ' for a vehicle of $800 \mathrm{~kg}$ mass, negotiating a turn on a $30^{\circ}$ banked road at maximum possible speed without skidding is__________ $\times 10^{3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}^{2}$.

  1. $10.2$

  2. $7.2$

  3. $12.4$

  4. $6.96$


Correct Option: 1

Solution:

At $\mathrm{v}_{\max }, \mathrm{f}$ will be limiting in nature.

$\therefore$ Balancing force in vertical direction,

$N \cos 30^{\circ}-\mathrm{mg}-\mu \mathrm{N} \cos 60^{\circ}=0$

$\Rightarrow \mathrm{N}\left[\cos 30^{\circ}-\mu \cos 60^{\circ}\right]=\mathrm{mg}$

$\therefore \mathrm{N}=\frac{800 \times 10}{(0.87-0.1)} \approx 10.2 \times 10^{3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}^{2}$

Hence option $1 .$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now