The number of chlorine atoms in

Question:

The number of chlorine atoms in $20 \mathrm{~mL}$ of chlorine gas at STP is $10^{21}$. (Round off to the Nearest Integer).

[Assume chlorine is an ideal gas at STP

$\mathrm{R}=0.083 \mathrm{~L}$ bar $\left.\mathrm{mol}^{-1} \mathrm{~K}^{-1}, \mathrm{~N}_{\mathrm{A}}=6.023 \times 10^{23}\right]$

Solution:

$\mathrm{PV}=\mathrm{nRT}$

$1.0 \times \frac{20}{1000}=\frac{\mathrm{N}}{6.023 \times 10^{23}} \times 0.083 \times 273$

$\therefore$ Number of $\mathrm{Cl}_{2}$ molecules, $\mathrm{N}=5.3 \times 10^{20}$

Hence, Number of Cl-atoms $=1.06 \times 10^{21}$

$\approx 1 \times 10^{21}$

 

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Samrat batt
Aug. 11, 2022, 4:03 p.m.
Good. And try to highlight the answer in the end
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