The oxidation states of ' p ' in

Question:

The oxidation states of ' $\mathrm{P}^{\prime}$ in $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7}, \mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{5}$ and $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}$, respectively, are :

  1. 7,5 and 6

  2. 5,4 and 3

  3. 5,3 and 4

  4. 6,4 and 5


Correct Option: , 3

Solution:

Oxidation state of $\mathrm{P}$ in $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7}, \mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{5}$ and $\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{6}$ is $5,3 \& 4$ respectively

$2 x+4(+1)+7(-2)=0$

$x=+5$

$\mathrm{H}_{4} \underline{\mathrm{P}_{2}} \mathrm{O}_{5}$

$2 x+4(+1)+5(-2)=0$

$x=+3$

$\mathrm{H}_{4} \underline{\mathrm{P}_{2}} \mathrm{O}_{6}$

$2 x+4(+1)+6(-2)=0$

$x=+4$

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