The perimeter of a trapezium is 52 cm
Question:

The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is

(a) 124 cm2 

(b) 118 cm2 

(c) 128 cm2 

(d) 112 cm2

Solution:

 

Explanation:

Given:

The perimeter of a trapezium = 52 cm

The sum of its parallel sides = 52 – (10+10) = 32 cm

We know that, the area of a trapezium = (1/2) (a+b) h

A = (1/2) (32) (8)

A = 128 cm2

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