The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
From the question it is given that,
Perimeters of first squares = 40m
Perimeter of second square = 96m
Let us assume side of first square = x1
and assume side of second square = x2
WKT, perimeter of first square = 4 × side
40 = 4x1
X1 = 40/4
X1 = 10 m
Then,
Perimeter of second square = 4 × side
96 = 4x2
X2 = 96/4
X2 = 24 m
As per the condition given in the question area of another square is equal to the first two squares.
Let us assume y2 be the area of another square.
So,
y2 = x12 + x22
y2 = 102 + 242
y2 = 100 + 576
y = √(676)
y = 26 m
Then,
Perimeter of another square = 4 × side
= 4 × y
= 4 × 26
= 104 m
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