Question:
The point on the curve $y=12 x-x^{2}$ where the slope of the tangent is zero will be
A. $(0,0)$
B. $(2,16)$
C. $(3,9)$
D. $(6,36)$
Solution:
Given that the curve $y=12 x-x^{2}$
The slope of the curve $\frac{d y}{d x}=12-2 x$
Given that the slope of the tangent $=0$
$\Rightarrow 12-2 x=0$
$\Rightarrow x=6$
So, $y=72-36$
$\Rightarrow y=36$
So, the correct option is $D$.