The point P(- 2, 4) lies on a circle

Question:

The point P(- 2, 4) lies on a circle of radius 6 and centre (3, 5).

 

Solution:

False

If the distance between the centre and any point is equal to the radius, then we say that point lie on the circle.

Now, distance between P (-2,4) and centre (3, 5)

$=\sqrt{(3+2)^{2}+(5-4)^{2}}$

$=\sqrt{5^{2}+1^{2}}$

$=\sqrt{25+1}=\sqrt{26}$

$\left[\because\right.$ distance between the points $\left(x_{1}, y_{1}\right)$ and $\left.\left(x_{2}, y_{2}\right), d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\right]$

which is not equal to the radius of the circle.

Hence, the point P(-2, 4) does not lies on the circle.

 

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