Question:
The product of two rational numbers is $\frac{-8}{9}$. If one of the numbers is $\frac{-4}{15}$, find the other.
Solution:
Let the other number be $\mathrm{x}$.
$\therefore \mathrm{x} \times \frac{-4}{15}=\frac{-8}{9}$
or $\mathrm{x}=\frac{-8}{9} \div \frac{-4}{15}$
or $\mathrm{x}=\frac{-8}{9} \times \frac{15}{-4}$
or $\mathrm{x}=\frac{10}{3}$
Thus, the other number is $\frac{10}{3}$.
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