The radii of two cylinders are in the ratio 3 : 5
Question:

The radii of two cylinders are in the ratio 3 : 5 and their heights are in the ratio 2 : 3. What is the ratio of their curved surface areas?

Solution:

Given that, $r_{1}: r_{2}=3: 5$ and $h_{1}: h_{2}=2: 3$

Now, the ratio of their curved surface area $s_{1}: s_{2}=2 \pi r_{1} h_{1}: 2 \pi r_{2} h_{2}$

$s_{1}: s_{2}=2 \pi r_{1} h_{1}: 2 \pi r_{2} h_{2}$

$=\left(\frac{r_{1}}{r_{2}}\right)\left(\frac{h_{1}}{h_{2}}\right)$

$\frac{s_{1}}{s_{2}}=\frac{3}{5} \times \frac{2}{3}=\frac{2}{5}$

Hence, $s_{1}: s_{2}=2: 5$

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