The radius of a circular plate is increasing at the rate of $0.01 \mathrm{~cm} / \mathrm{sec}$. The rate of increase of its area when the radius is $12 \mathrm{~cm}$, is
(a) $144 \pi \mathrm{cm}^{2} / \mathrm{sec}$
(b) $2.4 \pi \mathrm{cm}^{2} / \mathrm{sec}$
(c) $0.24 \pi \mathrm{cm}^{2} / \mathrm{sec}$
(d) $0.024 \pi \mathrm{cm}^{2} / \mathrm{sec}$
(c) $0.24 \pi \mathrm{cm}^{2} / \mathrm{sec}$
Let $r$ be the radius and $A$ be the area of the circular plate at any time $t .$ Then,
$A=\pi r^{2}$
$\Rightarrow \frac{d A}{d t}=2 \pi r \frac{d r}{d t}$
$\Rightarrow \frac{d A}{d t}=2 \pi(12)(0.01)$
$\Rightarrow \frac{d A}{d t}=0.24 \pi \mathrm{cm}^{2} / \mathrm{sec}$
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