The ranges and heights for two projectiles projected with the same initial velocity at angles

Range $\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$ and same for $\theta$ and $90-\theta$

So same for $42^{\circ}$ and $48^{\circ}$

Maximum height $\mathrm{H}=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{~g}}$

$\mathrm{H}$ is high for higher $\theta$

So $\mathrm{H}$ for $48^{\circ}$ is higher than $\mathrm{H}$ for $42^{\circ}$

Option (2)