Question:
The solubility product of Al(OH) 3 is 2.7 × 10-11. Calculate its solubility in gL-1 and also find out the pH of this solution. (Atomic mass of Al = 27 u).
Solution:
The equation of disassociation of Al(OH)3will be-
Al(OH)3 ⇌ Al3+ + 3OH-
We know that,
Ksp= [Al3+] [OH-] 3-
=(s) × (3s) 3 =27s4
S4 = Ksp/27
= 2.7x 10-11/27
s4= 10-12
s= (10-12)1/4 =10-3 mol/L
Now, molar mass of Al(OH)3 =78
Solubility= molar mass ×s
= 78 ×10-3
= 7.8 × 10-2 g/L
NOW, we know that-
pH = 14 – pOH
[OH]= 3s = 3 × 10-3
pOH= 3-log3
pH = 14 – 3 + log3
= 11.4771
Hence the pH of the solution will be 11.4771 and solubility in g/L will be 7.8×10-2 g/L.
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- JEE Main
- Exam Pattern
- Previous Year Papers
- PYQ Chapterwise
- Physics
- Kinematics 1D
- Kinemetics 2D
- Friction
- Work, Power, Energy
- Centre of Mass and Collision
- Rotational Dynamics
- Gravitation
- Calorimetry
- Elasticity
- Thermal Expansion
- Heat Transfer
- Kinetic Theory of Gases
- Thermodynamics
- Simple Harmonic Motion
- Wave on String
- Sound waves
- Fluid Mechanics
- Electrostatics
- Current Electricity
- Capacitor
- Magnetism and Matter
- Electromagnetic Induction
- Atomic Structure
- Dual Nature of Matter
- Nuclear Physics
- Radioactivity
- Semiconductors
- Communication System
- Error in Measurement & instruments
- Alternating Current
- Electromagnetic Waves
- Wave Optics
- X-Rays
- All Subjects
- Physics
- Motion in a Plane
- Law of Motion
- Work, Energy and Power
- Systems of Particles and Rotational Motion
- Gravitation
- Mechanical Properties of Solids
- Mechanical Properties of Fluids
- Thermal Properties of matter
- Thermodynamics
- Kinetic Theory
- Oscillations
- Waves
- Electric Charge and Fields
- Electrostatic Potential and Capacitance
- Current Electricity
- Thermoelectric Effects of Electric Current
- Heating Effects of Electric Current
- Moving Charges and Magnetism
- Magnetism and Matter
- Electromagnetic Induction
- Alternating Current
- Electromagnetic Wave
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- Atoms
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