Question:
The sum and product of the zeros of a quadratic polynomial are 3 and −10 respectively. The quadratic polynomial is
(a) $x^{2}-3 x+10$
(b) $x^{2}+3 x-10$
(c) $x^{2}-3 x-10$
(d) $x^{2}+3 x+10$
Solution:
(c) $x^{2}-3 x-10$
Given: Sum of zeroes, $\alpha+\beta=3$
Also, product of zeroes, $\alpha \beta=-10$
$\therefore$ Required polynomial $=x^{2}-(\alpha+\beta)+\alpha \beta=x^{2}-3 x-10$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.