Question:
The symmetric difference of A = {1, 2, 3} and B = {3, 4, 5} is
(a) {1, 2}
(b) {1, 2, 4, 5}
(c) {4, 3}
(d) {2, 5, 1, 4, 3}
Solution:
(b) {1, 2, 4, 5}
Here,
A = {1, 2, 3} and B = {3, 4, 5}
The symmetric difference of A and B is given by :-
$(A-B) \cup(B-A)$
Now, we have:
$(A-B)=\{1,2\}$
$(B-A)=\{4,5\}$
$(A-B) \cup(B-A)=\{1,2,4,5\}$
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