The total area of a page


The total area of a page is $150 \mathrm{~cm}^{2}$. The combined width of the margin at the top and bottom is $3 \mathrm{~cm}$ and the side $2 \mathrm{~cm}$. What must be the dimensions of the page in order that the area of the printed matter may be maximum?


Let $x$ and $y$ be the length and breadth of the rectangular page, respectively. Then,

Area of the page $=150$

$\Rightarrow x y=150$

$\Rightarrow y=\frac{150}{x}$                             ......(1)

Area of the printed matter $=(x-3)(y-2)$

$\Rightarrow A=x y-2 x-3 y+6$

$\Rightarrow A=150-2 x-\frac{450}{x}+6$

$\Rightarrow \frac{d A}{d x}=-2+\frac{450}{x^{2}}$

For maximum or minimum values of $A$, we must have

$\frac{d A}{d x}=0$


$\Rightarrow 2 x^{2}=450$

$\Rightarrow x=15$

Substituting the value of $x$ in $(1)$, we get



$\frac{d^{2} A}{d x^{2}}=\frac{-900}{x^{3}}$

$\Rightarrow \frac{d^{2} A}{d x^{2}}=\frac{-900}{(15)^{3}}$

$\Rightarrow \frac{d^{2} A}{d x^{2}}=\frac{-900}{3375}<0$

So, area of the printed matter is maximum when $x=15$ and $y=10$.

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now