The values of the crystal field stabilization energies for a high spin

Question:

The values of the crystal field stabilization energies for a high spin $\mathrm{d}^{6}$ metal ion in octahedral and tetrahedral fields, respectively, are:

  1. $-0.4 \Delta_{0}$ and $-0.27 \Delta_{\mathrm{t}}$

  2. $-1.6 \Delta_{0}$ and $-0.4 \Delta_{\mathrm{t}}$

  3. $-0.4 \Delta_{0}$ and $-0.6 \Delta_{\mathrm{t}}$

  4. $-2.4 \Delta_{0}$ and $-0.6 \Delta_{t}$


Correct Option: , 3

Solution:

For high spin octahedral field

$\mathrm{CFSE}=(4)\left(-0.4 \Delta_{0}\right)+2\left(0.6 \Delta_{0}\right)=-0.4 \Delta_{0}$

For high spin tetrahedral field

$\operatorname{CFSE}=3\left(-0.6 \Delta_{t}\right)+3\left(0.4 \Delta_{t}\right)=-0.6 \Delta_{t}$

 

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