Question:
The velocity-time graph (Fig. 6 ) shows the motion of a cyclist. Find
(i) its acceleration
(ii) its velocity and
(iii) the distance covered by the cyclist in 15 seconds.
Solution:
(i) Acceleration $=\frac{\text { Change in velocity }}{\text { time }}=0$
(ii) Velocity $=20 \mathrm{~m} \mathrm{~s}^{-1}$
(iii) Distance $=$ area under $v-t$ graph
$=v \times t=20 \mathrm{~ms}^{-1} \times 15 \mathrm{~s}=300 \mathrm{~m} .$
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