Question:
The volume $\mathrm{V}$ of an enclosure contains a mixture of three gases, $16 \mathrm{~g}$ of oxygen, $28 \mathrm{~g}$ of nitrogen and $44 \mathrm{~g}$ of carbon dioxide at absolute temperature $\mathrm{T}$. Consider $\mathrm{R}$ as universal gas constant.
The pressure of the mixture of gases is:
Correct Option: , 3
Solution:
(3)
$\mathrm{PV}=\left(\mathrm{n}_{1}+\mathrm{n}_{2}+\mathrm{n}_{3}\right) \mathrm{RT}$
$\mathrm{P} \times \mathrm{V}=\left[\frac{16}{32}+\frac{28}{28}+\frac{44}{44}\right] \mathrm{RT}$
$\mathrm{PV}=\left[\frac{1}{2}+1+1\right] \mathrm{RT}$