Question:
The zeros of the quadratic polynomial $x^{2}+88 x+125$ are
(a) both positive
(b) both negative
(c) one positive and one negative
(d) both equal
Solution:
(b) both negative
Let $\alpha$ and $\beta$ be the zeroes of $x^{2}+88 x+125$.
Then $\alpha+\beta=-88$ and $\alpha \times \beta=125$
This can only happen when both the zeroes are negative.
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