Question:
There are 6 multiple choice questions in an examination. How many sequences of answers are possible, if the first three questions have 4 choices each and the next three have 2 each?
Solution:
Number of ways of answering the first three questions = 4 each
Number of ways of answering the remaining three questions = 2 each
$\therefore$ Total number of ways of answering all the questions $=4 \times 4 \times 4 \times 2 \times 2 \times 2=512$
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