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There are two sources of light,

Question:

There are two sources of light,each emitting with a power of 100 W. One emits X-rays of wavelength 1nm and the other visible light at 500 nm. Find the ratio of a number of photons of X-rays to the photons of visible light of the given wavelength?

Solution:

Ex = hvx

Ev = hvv

Let nx and nv be the no.of photons from x-rays and visible light are of equal energies and they emit 100 W power.

nxhvx = nvhvv

nx/nv = vv/vx = λx/λv

nx/nv = 1 nm/500 nm

nx:nv = 1:500

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