Question:
There are two sources of light,each emitting with a power of 100 W. One emits X-rays of wavelength 1nm and the other visible light at 500 nm. Find the ratio of a number of photons of X-rays to the photons of visible light of the given wavelength?
Solution:
Ex = hvx
Ev = hvv
Let nx and nv be the no.of photons from x-rays and visible light are of equal energies and they emit 100 W power.
nxhvx = nvhvv
nx/nv = vv/vx = λx/λv
nx/nv = 1 nm/500 nm
nx:nv = 1:500
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