# Three coins are tossed. Describe

Question:

Three coins are tossed. Describe

(i) Two events which are mutually exclusive.

(ii) Three events which are mutually exclusive and exhaustive.

(iii) Two events, which are not mutually exclusive.

(iv) Two events which are mutually exclusive but not exhaustive.

(v) Three events which are mutually exclusive but not exhaustive.

Solution:

When three coins are tossed, the sample space is given by

S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

(i) Two events that are mutually exclusive can be

A: getting no heads and B: getting no tails

This is because sets A = {TTT} and B = {HHH} are disjoint.

(ii) Three events that are mutually exclusive and exhaustive can be

C: getting at least two heads

i.e.,

A = {TTT}

B = {HTT, THT, TTH}

C = {HHH, HHT, HTH, THH}

This is because $A \cap B=B \cap C=C \cap A=$ Фand $A \cup B \cup C=S$

(iii) Two events that are not mutually exclusive can be

B: getting at least 2 heads

i.e.,

A = {HHH}

B = {HHH, HHT, HTH, THH}

This is because $A \cap B=\{\mathrm{HHH}\} \neq \Phi$

(iv) Two events which are mutually exclusive but not exhaustive can be

B: getting exactly one tail

That is

A = {HTT, THT, TTH}

B = {HHT, HTH, THH}

It is because, $A \cap B=\Phi$, but $A \cup B \neq S$

(v) Three events that are mutually exclusive but not exhaustive can be

B: getting one head and two tails

C: getting one tail and two heads

i.e.,

A = {HHH}

B = {HTT, THT, TTH}

C = {HHT, HTH, THH}

This is because $A \cap B=B \cap C=C \cap A=\Phi$, but $A \cup B \cup C \neq S$