Tick (✓) the correct answer


Tick (✓) the correct answer

If x4y5z is exactly divisible by 9, then the least value of (x + y + z) is

(a) 3

(b) 6

(c) 9

(d) 0


(c) 9

A number is divisible by 9 if the sum of the digits is divisible by 9.


The lowest value of $(x+y+z)$ is equal to 0 for the number x4y5z to be divisible by 9 .

In this case, all x, y and z will be 0.

But x is the first digit, so it cannot be 0.

∴ x+4+y+5+z = 18

or x+y+z+9 = 18

or x+y+z = 9


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