**Question:**

Tick (✓) the correct answer

If the 4-digit number *x*27*y* is exactly divisible by 9, then the least value of (*x* + *y*) is

(a) 0

(b) 3

(c) 6

(d) 9

**Solution:**

(d) 9

If a number is divisible by 9, then the sum of the digits is divisible by 9.

$x+2+7+y=(x+y)+9$

For this to be divisible by 9, the least value of

But for x+y = 0, x and y both will be zero.

Since x is the first digit, it can never be 0.

∴ x + y + 9 = 18

or x + y = 9