Tick (✓) the correct answer:


Tick (✓) the correct answer:

The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 cm2. The distance between the parallel sides is

(a) 9 cm

(b) 7 cm

(c) 8 cm

(d) 12.5 cm


(c) 8 cm

Let the distance between the parallel sides be $\mathrm{x} \mathrm{cm}$.

Then, area of the trapezium $=\left\{\frac{1}{2} \times(19+13) \times \mathrm{x}\right\} \mathrm{cm}^{2}$

$=\left(\frac{1}{2} \times 32 \times x\right) \mathrm{cm}^{2}$

$=16 x \mathrm{~cm}^{2}$

But it is given that the area of the trapezium is $128 \mathrm{~cm}^{2} .$

$\therefore 16 x=128$

$\Rightarrow x=\frac{128}{16}$

$\Rightarrow x=8 \mathrm{~cm}$



Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now