Tick (✓) the correct answer


Tick (✓) the correct answer

If 64y8 is exactly divisible by 3, then the least value of y is

(a) 0

(b) 1

(c) 2

(d) 3


(a) 0

If a number is divisible by 3, then the sum of the digits is also divisible by 3.



This is divisible by 3 as $y$ is equal to 0 .

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