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If 5x6 is exactly divisible by 3, then the least value of x is
If a number is exactly divisible by 3, the sum of the digits must also be divisible by 3.
$5+x+6=11+x$ must be divisible by 3 .
The smallest value of $x$ is 1 .
$\Rightarrow x+11=12$ is divisible by $3 .$