Tick (✓) the correct answer


Tick (✓) the correct answer:

A photograph of a bacteria enlarged 50000 times attains a length of 5 cm. The actual length of bacteria is

(a) 1000 cm

(b) 10−3 cm

(c) 10−4 cm

(d) 10−2 cm


(c) $10^{-4} \mathrm{~cm}$

Let $x \mathrm{~cm}$ be the actual length of the bacteria.

The larger the object, the larger its image will be.

Now, $\frac{x}{1}=\frac{5}{50000}=10^{-4} \mathrm{~cm}$

Hence, the actual length of the bacteria is $10^{-4} \mathrm{~cm}$.

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