Tickets numbered from 1 to 12 are mixed up together, and then a ticket is withdrawn at random.
Question:

Tickets numbered from 1 to 12 are mixed up together, and then a ticket is withdrawn at random. Find the probability that the ticket has a number which is a multiple of 2 or 3.

Solution:

We know that,

Probability of occurrence of an event

$=\frac{\text { Total no.of Desired outcomes }}{\text { Total no.of outcomes }}$

Total no. of outcomes are 12

Desired output is picking a number which is multiple of 2 or 3 . So, desire outputs are 2 , $3,4,6,8,9,10,12$. Total no.of desired outputs are 8

Therefore, the probability of getting a number which is multiple of 2 or 3

$=\frac{8}{12}$

$=\frac{2}{3}$

Conclusion: Probability of picking a ticket which is multiple of 2 or 3 is $\frac{2}{3}$