Two brands of chocolates are available in packs of 24 and 15 respectively.

We are given that two brands of chocolates are available in packs of 24 and 15 respectively. If he needs to buy an equal number of chocolates of both kinds, then find least number of boxes of each kind he would need to buy.

Given that

Number of chocolates of 1st brand in one pack =24

Number of chocolates of 2nd brand in one pack = 15.

Therefore, the least number of chocolates he need to purchase is

L.C.M. of 24 and $15=2 \times 2 \times 2 \times 3 \times 5$

$=120$

Therefore, the number of packet of 1st brand is

$\frac{120}{24}=5$

And the number of packet of 2nd brand is

$\frac{120}{15}=8$