# Two coins are tossed simultaneously. Find the probability of getting

Question:

Two coins are tossed simultaneously. Find the probability of getting

Solution:

When two coins are tossed simultaneously, all possible outcomes are HH, HT, TH and TT.

Total number of possible outcomes = 4

(i) Let E be the event of getting exactly one head.

Then, the favourable outcomes are HT and TH.

​Number of favourable outcomes = 2

$\therefore P($ getting exactly 1 head $)=\frac{\text { Number of favourable outcomes }}{\text { Total number of possible outcomes }}=\frac{2}{4}=\frac{1}{2}$

(ii) Let E be the event of getting at most one head.

Then, the favourable outcomes are HT, TH and TT.

​Number of favourable outcomes = 3

$\therefore P$ (getting at most 1 head) $=\frac{\text { Number of favourable outcomes }}{\text { Total number of possible outcomes }}=\frac{3}{4}$

(iii) Let E be the event of getting at least one head.

Then, the favourable outcomes are HT, TH and HH

Number of favourable outcomes $=3$

$\therefore P($ getting at least 1 head) $)=\frac{\text { Number of favourable outcomes }}{\text { Total number of possible outcomes }}=\frac{3}{4}$