# Two cubes, each of volume 512 cm3

Question:

Two cubes, each of volume $512 \mathrm{~cm}^{3}$ are joined end to end. Find the surface area of the resulting cuboid.

Solution:

Given that,

Volume of the cube $=512 \mathrm{~cm}^{3}$

$\Rightarrow$ side $^{3}=512$

$\Rightarrow$ side $^{3}=8^{3}$

⇒ side = 8 cm

Dimensions of the new cuboid formed

Length (l) = 8 + 8 = 16 cm, Breadth (b) = 8 cm, Height (h) = 8 cm

Surface area = 2(lb + bh + hl)

= 2(16 * 8 + 8 * 8 + 16 * 8)

$=640 \mathrm{~cm}^{2}$

Therefore, Surface area is $640 \mathrm{~cm}^{2}$.