Two dices are rolled.


Two dices are rolled. If both dices have six faces numbered $1,2,3,5,7$ and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is :

  1. $\frac{4}{9}$

  2. $\frac{17}{36}$

  3. $\frac{5}{12}$

  4. $\frac{1}{2}$

Correct Option: , 2



So, $P(E)=\frac{17}{36}$

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