Two motor mechanics, Raju and Siraj, working together can overhaul a scooter in 6 hours.

Question:

Two motor mechanics, Raju and Siraj, working together can overhaul a scooter in 6 hours. Raju alone can do the job in 15 hours. In how many hours can Siraj alone do it?

Solution:

Time taken by Raju $=15 \mathrm{~h}$

Work done by Raju in $1 \mathrm{~h}=\frac{1}{15}$

Time taken by Raju and Siraj working together $=6 \mathrm{~h}$

Work done by Raju and Siraj in $1 \mathrm{~h}=\frac{1}{6}$

Work done by Siraj in $1 \mathrm{~h}=($ work done by Raju and Siraj $)-($ work done by Raju $)$

$=\frac{1}{6}-\frac{1}{15}=\frac{5-2}{30}=\frac{3}{30}=\frac{1}{10}$

$\therefore$ Siraj will take $10 \mathrm{~h}$ to overhaul the scooter by himself.

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