Question:
Two particles A and B of equal masses are suspended from two massless springs of spring constants $K_{1}$ and $K_{2}$ respectively.If the maximum velocities during oscillations are equal, the ratio of the amplitude of $A$ and $B$ is
Correct Option: , 4
Solution:
(4) $\mathrm{A}_{1} \omega_{1}=\mathrm{A}_{2} \omega_{2}$
$A_{1} \sqrt{\frac{k_{1}}{m}}=A_{2} \sqrt{\frac{k_{2}}{m}}$
$\frac{A_{1}}{A_{2}}=\sqrt{\frac{k_{2}}{k_{1}}}$
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