Two vectors have magnitudes

Question:

Two vectors have magnitudes $2 \mathrm{~m}$ and $3 \mathrm{~m}$. The angle between them is $60^{\circ}$. Find (a) the scalar product of the two vectors, (b) the magnitude of their vector product?

Solution:

We have $a=2 m, b=3 m$.

$\Theta=60^{\circ}$ is the angle between the two vectors

Scalar product between the two vectors $=a \cdot b=$

$2 \times 3 \times \cos \left(60^{\circ}\right)=3 \mathrm{~m}^{2}$

Vector product between the two vectors $=a \times b=$

$2 \times 3 \times \sin \left(60^{\circ}\right)=3 \sqrt{3} \mathrm{~m}^{2}$

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