**Question:**

**Using contrapositive method prove that if n2 is an even integer, then n is also an even integers.**

**Solution:**

Let us assume

p: n2 is an even integer.

~p: n is not an even integer

q: n is also an even integer

~q=n is not an even integer.

Since, in the contrapositive, a conditional statement is logically equivalent to its contrapositive.

Therefore,

~q → ~p = If n is not an even integer then n2 is not an even integer.

Hence, ~q is true → ~p is true.

Objective type questions: