Question:
Very-Short-Answer Questions
Show that $x=-3$ is a solution of $x^{2}+6 x+9=0$.
Solution:
The given equation is $x^{2}+6 x+9=0$.
Putting x = −3 in the given equation, we get
LHS $=(-3)^{2}+6 \times(-3)+9=9-18+9=0=$ RHS
∴ x = −3 is a solution of the given equation.
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