What is (a) the highest,

solution:

(a) The highest resistance is secured when all the resistors are connected in series. The equivalent resistance is given by

$R_{g}=4 \Omega+8 \Omega+12 \Omega+24 \Omega=48 \Omega$

(2) The lowest resistance is secured when all the four coils are connected in parallel. The equivalent resistance is given by,

$\frac{1}{R_{e}}=\frac{1}{4}+\frac{1}{8}+\frac{1}{12}+\frac{1}{24}=\frac{6+3+2+1}{24}=\frac{12}{24}=\frac{1}{2} \quad$ or $\quad R_{e}=2 \Omega$