What is the effect of the following processes on the bond order in N2 and O2?
(i) N2→ N2+ + e-
(ii) O2→ O2+ + e-
(i) N2 is having 14 electrons when it donates one electron, these electrons are removed from the Bonding molecular orbital. BO for N2 = 3
(ii) O2 has 16 electrons, 8 electrons in the molecular orbitals and 4 in the antibonding molecular orbitals.
BO for O2 = 2