What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 , in it's aqueous solution?
Question:
What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 , in it's aqueous solution?
Correct Option: 1
Solution:
Electronic configuration of divalent metal ion having atomic number 25 is
Total number of unpaired electrons $=5$
$\mu$ (Magnetic moment) $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ BM
where $n=$ number of unpaired $e^{-}$
$\therefore \mu=\sqrt{5(5+2)}=\sqrt{35} \mathrm{BM}=5.92 \mathrm{BM}$
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